Answer: The length of the rectangle is 16 yards and the width is 12 yards.
Step-by-step explanation:
The length is 4 yds longer than the width. Let's remove that from the perimeter so that the perimeter will be as if all sides had the same length (remember there are 2 sides for length and 2 sides for width).
[tex]56-4-4\\48[/tex]
Now we made it so that the extra 4 yards are gone and all sides are equal like a square. Now we can divide by 4 to determine the length of each of the now equal sides
[tex]\frac{48}{4} =12[/tex]
So all of the sides are 12, 12, 12, and 12. To two of the sides we can add back the extra 4 yards we took out giving us sides of 12, 12, 16, and 16.
Let's add it all together and see if it makes the perimeter of 56
[tex]12+12+16+16\\24+32\\56[/tex]
It does! Since the length is 4 yds longer than the width the length is 16 and width is 12.
