Answer: 10 V, 40 V
Explanation:
Given
Resistors are [tex]500\Omega[/tex] and [tex]2000\Omega[/tex]
Power supply [tex]V=60\ V[/tex]
Voltmeter internal resistance [tex]r=2000\ \Omega[/tex]
When it connected around [tex]500\Omega[/tex] resistance, effective resistance becomes
[tex]\Rightarrow \dfrac{1}{R}=\dfrac{1}{500}+\dfrac{1}{2000}\\\\\Rightarrow R=\dfrac{2000}{5}\\\\\Rightarrow R=400\ \Omega[/tex]
Total resistance in series [tex]R_{net}=2400\ \Omega[/tex]
Current in circuit
[tex]I=\dfrac{60}{2400}=\dfrac{1}{40}\ A[/tex]
Voltage around [tex]500\Omega[/tex] resistance is
[tex]V=\dfrac{1}{40}\times 400\\\\V=10\ V[/tex]
(B) when voltmeter is connected around [tex]2000\Omega[/tex] resistor
Net resistance around it
[tex]\Rightarrow \dfrac{1}{R}=\dfrac{1}{2000}+\dfrac{1}{2000}\\\\\Rightarrow R=1000\ \Omega[/tex]
Total resistance [tex]R_{net}=1500\ \Omega[/tex]
Current in circuit
[tex]I=\dfrac{60}{1500}=\dfrac{1}{25}\ A[/tex]
Voltage around [tex]2000\Omega[/tex] resistor
[tex]V=\dfrac{1}{25}\times 1000\\\\V=40\ V[/tex]
