Answer:
x=4 and y=−2
Step-by-step explanation:
Let's solve your system by substitution.
3x+8y=−4;2x−4y=16
Step: Solve 3x+8y=−4 for x:
3x+8y=−4
3x+8y+−8y=−4+−8y(Add -8y to both sides)
3x=−8y−4
3x/3=−8y−4/3 (Divide both sides by 3)
x=−8/3y+−4/3
Step: Substitute −8/3y+−4/3 for x in 2x−4y=16:
2x−4y=16
2(−8/3y+−4/3)−4y=16
−28/3y+−8/3=16 (Simplify both sides of the equation)
−28/3y+−8/3+8/3=16+8/3 (Add 8/3 to both sides)
−28/3y=56/3
−28/3y/−28/3=56/3/−28/3 (Divide both sides by (-28)/3)
y=−2
Step: Substitute−2 for y in x=−8/3y+−4/3:
x=−8/3y+−4/3
x=−8/3(−2)+−4/3
x=4 (Simplify both sides of the equation)
So the Answers are: x=4 and y=−2 or u can switch it around y=−2 and x=4
