Answer:
Answer:
A) 0.15
B) 0.36
Step-by-step explanation:
First Box consist 1 red pills and 19 blue pills
second box consist 6 red pills and 14 blue pills
Third box consist 2 red pills and 18 blue pills
a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}=
3
1
×
20
1
+
3
1
×
20
6
+
3
1
×
20
2
\frac{1}{60} (1+6+2) = 0.15
60
1
(1+6+2)=0.15
b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}
3
1
20
C
11
1
C
1
×
19
C
10
+
3
1
20
C
11
6
C
1
×
14
C
10
+
3
1
20
C
11
2
C
1
×
18
C
10
= \frac{1}{3} 1.106 = 0.368=
3
1
1.106=0.368
Step-by-step explanation:
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