Respuesta :

Answer:

I think its y^-3

Step-by-step explanation:

Since y^-3/y^-2 are both negatives they would swap places to become positive - y^2/y^3

then using rules of exponents you would subtract the exponents witch would be y^-3

Answer:

[tex]\frac{1}{y^{3} }[/tex]

Step-by-step explanation:

[tex]\frac{y^{-5}}{y^{-2}}[/tex]

Apply exponent rule [tex]\frac{x^a}{x^b}=x^{a-b}[/tex]

[tex]=y^{-5-\left(-2\right)}[/tex]

Apply rule [tex]-\left(-a\right)=a[/tex]

[tex]=y^{-5+2}[/tex]

Add/Subtract the numbers -5+2=-3

[tex]=y^{-3}[/tex]

Apply exponent rule [tex]a^{-b}=\frac{1}{a^b}[/tex]

[tex]=\frac{1}{y^3}[/tex]