Answer:
1695.6 cubic feet
Step-by-step explanation:
Given that,
The corn fills 25% of the height of the silo.
The diameter of silo, d = 12 feet
Radius, r = 6 feet
Height, h = 60 feet
The volume of the part of the silo that is filled with corn is given by :
[tex]V=25\%\ of\ \pi r^2 h\\\\=\dfrac{25}{100}\times 3.14\times 6^2\times 60\\\\V= $1695.6\ feet^3[/tex]
So, the required volume is equal to 1695.6 cubic feet.
