Answer:
The answer is below
Step-by-step explanation:
The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:
[tex]AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\[/tex]
Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:
The distance between K and L = KL = [tex]\sqrt{(-1-3)^2+(1-4)^2} =5\ units[/tex]
The distance between J and L = JL = [tex]\sqrt{(-1-3)^2+(1-(-3))^2} =4\sqrt{2} \ units[/tex]
The distance between K and J = JK = [tex]\sqrt{(3-3)^2+(-3-4)^2} =7\ units[/tex]
Therefore, the perimeter of triangle JKL is:
Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units
