Respuesta :
Answer:
F = 6.12 10ā»Ā¹āµ N, Ā Ā a = 3.66 10Ā¹Ā² m / sĀ²
Explanation:
The magnetic force is
Ā Ā Ā Ā Ā Ā F = q v x B
bold letters indicate vectors, the modulus of this expression is
Ā Ā Ā Ā Ā Ā F = q v B sin Īø
as they indicate that the magnetic field is vertical the proton moves horizontally the angle is 90Āŗ
suppose that the energy of the proton is totally kinetic
Ā Ā Ā Ā E = 5.3 MeV (10ā¶ 1.6 10ā»Ā¹ā¹J / 1 eV) = 8.48 10ā»Ā¹Ā³ J
Ā Ā Ā Ā E = K = Ā½ m vĀ²
Ā Ā Ā Ā v = [tex]\sqrt{2E/m}[/tex][tex]\sqrt{2 \ 8.48 \ 10^{-13} / 1.67 \ 10^{-27}}[/tex]
Ā Ā Ā Ā v = [tex]\sqrt{2 \ 8.48 \ 10^{-13} / 1.67 \ 10^{-27}}[/tex]
Ā Ā Ā Ā v = [tex]\sqrt{10.155 \ 10^{14}}[/tex]
Ā Ā Ā Ā v = 3.19 10ā· m / s
we calculate
Ā Ā Ā Ā F = 1.6 10ā»Ā¹ā¹ Ā 3.19 10ā· Ā 1.2 10ā»Ā³
Ā Ā Ā Ā F = 6.12 10ā»Ā¹āµ N
Ā Ā Ā Ā
The direction of this out is given by the right hand rule,
thumb in the direction of speed, south to north
fingers extended in the direction of the magnetic field, vertical
the probe points in the direction of the force for a positive charge, Ā East
To calculate the acceleration we use Newton's second law
Ā Ā Ā Ā F = ma
Ā Ā Ā Ā a = F / m
Ā Ā Ā Ā a = 6.12 10ā»Ā¹āµ / 1.67 10ā»Ā²ā·
Ā Ā Ā Ā a = 3.66 10Ā¹Ā² m / sĀ²
the direction of the acceleration is the same as the direction of the force
