Respuesta :
Answer:
910 millibars
Step-by-step explanation:
According to the Question,
- Given That, The mean sustained wind velocity equation [tex]v=6.3*\sqrt{1013-p}[/tex] And The mean sustained wind velocity is 64m/s (v=64) . where, p is the air pressure(in millibars).
Now, the air pressure at the center of a hurricane when the mean sustained wind velocity is 64 m/s is
[tex]64=6.3*\sqrt{1013-p}\\\frac{64}{6.3} = \sqrt{1013-p}\\[/tex]
on squaring both sides we get,
(10.1587)² = 1012 - p ⇒ p = 908.80≈910millibar
p = 910millibars air pressure .
