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The brachialis attaches to the forearm .035 m from the elbow at an angle of 32 deg. If the brachialis produces 750 N of force, what is the magnitude of the stabilizing component of the brachialis force

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okpalawalter8

Answer:

[tex]XY=636N[/tex]

Explanation:

From the question we are told that:

Distance [tex]d=0.35m[/tex]

Angle [tex]\theta=32\textdegree[/tex]

Force [tex]F=750N[/tex]

Generally the equation for magnitude of the stabilizing component of the brachialis force is mathematically given by

 [tex]XY=Fcos\theta[/tex]

 [tex]XY=750cos 32\textdegree[/tex]

 [tex]XY=636N[/tex]

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