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A large lamp is to be supported by a tube 12 feet long, you have been asked to consider a bronze or copper tube. The load is 10500 lbs. The inner diameter must be .5 inches. Use the tables in the book to get the tensile stresses. Find the diameter of the tube and the elongation

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okpalawalter8

Answer:

[tex]E=17.52inch[/tex]

Step-by-step explanation:

Tube support Length [tex]l= 12feet=240inches[/tex]

Weight [tex]W=10500[/tex]

Diameter [tex]d=0.5inches[/tex]

Generally the equation for stress is mathematically given by

 [tex]Stress=\frac{Force}{Area}[/tex]

Where

 [tex]Area=\pi/4(D_o^2-0.5^2)[/tex]

Therefore

 [tex]110*1000=\frac{10500}{\pi/4(D_o^2-0.5^2)}[/tex]

 [tex]D_0=0.61inches[/tex]

Generally the equation for Elongation is mathematically given by

 [tex]E=\frac{Pl}{AE}[/tex]

 [tex]E=\frac{10500*240}{\pi/4(0.61^2-0.5^2)*1500*10^3}[/tex]

 [tex]E=17.52inch[/tex]

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