Answer: 0.129449
Step-by-step explanation:
Let x be the random variable that represents the population of quarters.
Given: The population of quarters have a mean weight of 5.670 g and a standard deviation of 0.062 g.
The probability that a randomly selected quarter has a weight less than 5.600 g:
[tex]P(X<5.600)=P(\dfrac{X-mean}{standard\ deviation}<\dfrac{5.600-5.670}{0.062})\\\\=P(Z<-1.129)\\\\=1-P(1.129)\\\\=1-0.870551\\\\=0.129449[/tex]
The required probability = 0.129449