Answer:
Wavelength = 0.143 m
Explanation:
Given that,
The length of a cable, l = 48 m
Mas of the object, m = 140 jg
The tension in the cable, T = 2222 N
The frequency of the cable, f = 2 Hz
We need to find the wavelength of the resulting wave on the cable.The speed of a wave in the string is given by :
[tex]v=\dfrac{\sqrt{\dfrac{T}{m/L}}}{2L}[/tex]
Put all the values,
[tex]v=\dfrac{\sqrt{\dfrac{2222}{140/48}}}{2(48)}\\\\=0.287\ m/s[/tex]
Let the wavelength is [tex]\lambda[/tex]. We know that,
[tex]\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{0.287}{2}\\\\=0.143\ m[/tex]
So, the wavelength of the resulting wave is 0.143 m.