Answer:
Hence the correct option is the distribution with n = 225 will have a smaller standard error.
Step-by-step explanation:
Now the standard deviation is
[tex]S.E=\frac{\sigma }{\sqrt{n}}[/tex]
If n = 100 then consider [tex]\sigma =6[/tex]
[tex]S.E=\frac{6}{\sqrt{100}}=0.6[/tex].
If n= 225 then consider [tex]\sigma =6[/tex]
[tex]S.E=\frac{6}{\sqrt{225}}=0.4[/tex].
Here the distribution with n = 225 will have a smaller standard error.