Answer:
his displacement is 772.85 ft
Explanation:
Given;
initial velocity of his jump, u = 2 ft/s
final velocity of his jump, v = - 223 ft/s
time of motion, t = 7 seconds
acceleration due to gravity, g = 32.17 ft/s²
Let downward motion = positive direction
Let his displacement after 7s = Δh
Apply the following kinematic equation to determine his displacement.
[tex]v^2 = u^2 + 2g\Delta h\\\\(-223)^2 = (2)^2 + (2\times 32.17)\Delta h\\\\49,729 = 4 + 64.34\Delta h\\\\-64.34 \Delta h = 4 - 49,729\\\\-64.34 \Delta h = -49,725\\\\\Delta h = \frac{49,725}{64.34} \\\\\Delta h = 772.85 \ ft[/tex]
Therefore, his displacement is 772.85 ft
