If x is a positive integer, for how many different values of x is StartRoot StartFraction 48 Over x EndFraction EndRoot a whole number? 2 3 6 10

Respuesta :

Answer:

3

Step-by-step explanation:

According To the Question,

  • Given that, 'x' is a positive integer . And We have to find the number of different values of 'x', So that the value of [tex]\sqrt{\frac{48}{x} }[/tex] is a Whole number.

Then First, we have to find those values of 'x' for which the given fraction is a square.

We Know, All the factors of 48 are {1,2,3,4,6,8,12,16,24,48} .

Now, From the above factors, only (3,12 & 48) can give us a square number.

Therefore,

  • If x=3, Then [tex]\sqrt{\frac{48}{3} } = \sqrt{16}[/tex] ⇒ 4
  • If, x=12, Then [tex]\sqrt{\frac{48}{12} } = \sqrt{4}[/tex] ⇒ 2
  • If, x=48, Then [tex]\sqrt{\frac{48}{48} } = \sqrt{1}[/tex] ⇒ 1

Thus, There are 3 whole numbers (3,12,48).

Answer:

b. 3

edge 2021

hope it helps :)

mark brainliest!