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What is the equilibrium expression for the reaction below?
C(s) + O2(9)
2009)
[0][c]
O A.
[CO]
O B.
1
C с
OC.
[co]
[0][c]
CO2]
D.

What is the equilibrium expression for the reaction below Cs O29 2009 0c O A CO O B 1 C с OC co 0c CO2 D class=

Respuesta :

unknown767

Answer:

C

Explanation:

because it is product over reactants. hope this helps :)

The equilibrium expression for the reaction C(s) +[tex]O_{2}[/tex](g) ⇄ [tex]CO_{2}[/tex] (g) will be

[[tex]CO_{2}[/tex] ] / [ [tex]O_{2}[/tex] ].

What is  equilibrium?

Chemical equilibrium is a state where no net change in the quantities of reactants as well as products takes place during a reversible chemical reaction.

The given reaction is C(s) +[tex]O_{2}[/tex](g) ⇄ [tex]CO_{2}[/tex] (g) .

It is known that solid phase is not considered in equilibrium.

Hence, equilibrium expression = [[tex]CO_{2}[/tex] ] / [ [tex]O_{2}[/tex] ].

Therefore, the correct answer will be option (D).

To know more about equilibrium.

https://brainly.com/question/13463225

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