Somebody please help asap

Answer:
B. [tex] 4x^2 + \frac{3}{2}x - 7 [/tex]
Step-by-step explanation:
[tex] f(x) = \frac{x}{2} - 3 [/tex]
[tex] g(x) = 4x^2 + x - 4 [/tex]
(f + g)(x) = f(x) - g(x)
= [tex] \frac{x}{2} - 3 + 4x^2 + x - 4 [/tex]
Add like terms
[tex] = 4x^2 + \frac{x}{2} + x - 3 - 4 [/tex]
[tex] = 4x^2 + \frac{3x}{2} - 7 [/tex]
[tex] = 4x^2 + \frac{3}{2}x - 7 [/tex]