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What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?
SER
O y=-*x+33
y=-*x+36
O y =
O y = 4x - 16
O y = 4x + 16
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sqdancefan

9514 1404 393

Answer:

  y = 4x + 16

Step-by-step explanation:

You can replace the point coordinates in the given point-slope form to get ...

  y - 32 = 4(x -4)

Then rearrange to put this into slope-intercept form.

  y = 4x -16 +32 . . . . eliminate parentheses, add 32

  y = 4x +16 . . . . . . . . simplify

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