Respuesta :
Given:
In triangle [tex]ABC, AC=13, BC=84, AB=85[/tex].
To find:
The measure of angle C.
Solution:
Law of Cosines:
[tex]\cos C=\dfrac{a^2+b^2-c^2}{2ab}[/tex]
[tex]\cos C=\dfrac{BC^2+AC^2-AB^2}{2(BC)(AC)}[/tex]
Substituting the given values, we get
[tex]\cos C=\dfrac{(84)^2+(13)^2-(85)^2}{2(84)(13)}[/tex]
[tex]\cos C=\dfrac{7056+169-7225}{2184}[/tex]
[tex]\cos C=\dfrac{0}{2184}[/tex]
[tex]\cos C=0[/tex]
Taking cos inverse on both sides, we get
[tex]C=\cos^{-1}(0)[/tex]
[tex]C=90^\circ[/tex]
Therefore, the measure of angle C is 90 degrees.
Answer:
eason
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eason
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eason
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boy
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eason
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eason
Step-by-step explanation:
boy
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eason
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boy
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