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There are10 members on a board of directors. If they must elect a chairperson, a secretary, and a treasurer, howmany different slates of candidates are possible

Respuesta :

Answer:

The answer is "720"

Step-by-step explanation:

The amount of different slates candidates:

[tex]n=\frac{N!}{(N-k)!}\\\\[/tex]

   [tex]=\frac{10!}{(10-3)!}\\\\=\frac{10!}{7!}\\\\=\frac{10\times 9 \times 8 \times 7! }{7!}\\\\=10\times 9 \times 8\\\\=90\times 8\\\\=720[/tex]

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