Answer: [tex]\left | 2t-5\right |,\ 2,\ 2t-5[/tex]
Step-by-step explanation:
Given
Position of the particle moving along the coordinate axis is given by
[tex]s(t)=t^2-5t+1[/tex]
Speed of the particle is given by
[tex]\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |[/tex]
Acceleration of the particle is
[tex]\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2[/tex]
velocity can be negative, but speed cannot
[tex]\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5[/tex]
