Answer:
2x + 3y - 5 = 0
Step-by-step explanation:
(4 , -1) & (-2,3)
[tex]Slope =\frac{y_{2}-y_{1}}{x_{2}-x_1}}\\\\=\frac{3-[-1]}{-2-4}\\\\=\frac{3+1}{-6}\\\\=\frac{4}{-6}\\\\=\frac{-2}{3}[/tex]
m = -2/3; (4 , -1)
y - y1 = m(x - x1)
[tex]y - [-1]= \frac{-2}{3}(x-4)\\\\y + 1 =\frac{-2}{3}x -4*\frac{-2}{3}\\\\y + 1 =\frac{-2}{3}x+\frac{8}{3}[/tex]
Multiply the equation by 3
3y + 3 = -2x + 8
3y = -2x + 8 - 3
3y = -2x + 5
2x + 3y - 5 = 0
