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A baseball is projected upward at 64 feet per second. It can be approximated by the equation -16t^2+64t. The baseball reaches it maximum height at the vertex. That can be gotten from x= −/2a . How long until the baseball reaches its full height? Note a quadratic equation can be written as ax^2+bx+c

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jessmzhou4

Answer:

f(t) = -16t²+64t

  • t = number of seconds
  • f(t) = height (in feet)

The x-coordinate(t) of the vertex can be found using formula [tex]\frac{-b}{2a}[/tex], where:

  • a = -16
  • b = 64

Therefore the t-value of the vertex is:

[tex]\frac{-64}{2(-16)} =\frac{-64}{-32} =2[/tex]

The baseball will reach its maximum height after two seconds.

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