Explanation:
Molarity(M) of a solution is defined as the number of moles of solute(n) present in one liter of solution(V).
[tex]M=\frac{n}{V}[/tex]
The number of moles(n) can be calculated as shown below:
[tex]n=\frac{mass of solute}{molar mass of solute}[/tex]
Molar mass of dextrose is 198.17 g/mol
Molar mass of NaCl is 58.5 g/mol.
Volume of the solution =250.0mL=0.250 L
The number of moels of dextrose([tex]n_{d}[/tex]) is:
[tex]n_{d} =\frac{13.252g}{198.17g/mol} \\=0.0669mol[/tex]
The number of moles of NaCl is:
[tex]n_{NaCl} =\frac{0.686 g}{58.5g/mol} \\\\=0.01177 mol[/tex]
Thus, the molarity of dextrose is:
[tex]M_d=\frac{n_d}{0.250 L} \\=0.0669mol/0.250L\\=0.268 M[/tex]
The molarity of NaCl is:
[tex]M_Na_Cl=\frac{n_d}{0.250 L} \\\\=0.0118mol/0.250L\\\\=0.0472 M[/tex]
Answer:
The molarity of dextrose is 0.268 M.
The molarity of NaCl is 0.0472 M.
