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A group of dental researchers are testing the effects of acidic drinks on dental crowns. They have five containers of crowns labeled V, W, X, Y, and Z. They will randomly select one of the containers to be the control for the experiment by drawing one of five well-mixed slips of paper with the same labels from a hat. Which of the following is the probability model for the control container?

Respuesta :

MrRoyal

Answer:

[tex]\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}[/tex]

Step-by-step explanation:

Given

[tex]S = \{V,W,X,Y,Z\}[/tex]

[tex]n(S) = 5[/tex]

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

[tex]P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20[/tex]

So, the probability model is:

[tex]\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}[/tex]