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How many moles of KOH are there in 27.5 mL of 0.250 M KOH?

Question 2 options:

4.31 × 10−3 mol KOH


6.88 × 10−3 mol KOH


7.24 × 10−3 mol KOH


8.13 × 10−3 mol KOH


9.21 × 10−3 mol KOH

Respuesta :

samueladesida43

Answer:

6.88 × 10^-3mol

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:

number of moles = molarity × volume

Volume of KOH = 27.5mL = 27.5/1000

= 0.0275L

n = 0.0275 × 0.250

n = 0.006875 mol

n = 6.88 × 10^-3mol

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