Answer:
Perimeter of the park = 70 cm
Step-by-step explanation:
Perimeter of the park = perimeter of the 2 semicircles + 2(length of the rectangle)
Perimeter = 2πr + 2(BC)
✔️Perimeter of the 2 semicircles = 2πr
Where,
radius (r) = ½(AB) = ½(7)
r = 3.5 cm
Perimeter = 2*π*3.5 = 7*π
Perimeter of the two semicircles = 21.9911486 ≈ 22 cm
✔️Find BC using Pythagorean theorem:
Thus,
BC = √(AC² - AB²)
AC = 25
AB = 7
BC = √(25² - 7²) = √576
BC = 24
✔️Perimeter of the park = perimeter of the 2 semicircles + 2(length of the rectangle)
Perimeter of the park = 22 + 2(24)
= 22 + 48
= 70 cm
