Answer: [tex]V=0.0028278\ m^3[/tex]
Step-by-step explanation:
Given
Length of the pipe [tex]l=4\ m[/tex]
Inside diameter of the pipe [tex]d_i=4\ cm[/tex]
Outside diameter of the pipe [tex]d_o=5\ cm[/tex]
Volume of the pipe
[tex]\Rightarrow V=\dfrac{\pi }{4}[d_o^2-d_i^2]\\\\\text{Insert the values}\\\\\Rightarrow V=\dfrac{\pi}{4}[5^2-4^2]\times 10^{-4}\times 4\\\\\Rightarrow V=28.278\times 10^{-4}\ m^3\\\\\Rightarrow V=0.0028278\ m^3[/tex]