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Question 2 (1 point)
Match each situation to a linear system below.
A child has a piggy bank full
of $1 and $2 coins totalling
$37.
There are 25 more $1 coins
than there are $2 coins.
1. x + 2y = 37
x - y = 25
An exam that is worth 37
marks contains 25
questions.
The questions are either
worth 1 mark or 2 marks.
2. x + 2y = 37
x + y = 25
18
3. x - 2y = 37
x + y = 25
The sum of two numbers is
25.
The first number is 37 more
than 2 times the second
number

Respuesta :

abidemiokin

Answer:

See answers below

Step-by-step explanation:

For the expression

The sum of two numbers is  25.  The first number is 37 more  than 2 times the second  number

Let the two numbers be x and y

If the sum is 25, then;

x + y = 25 .... 1

37 more  than 2 times the second  the number is expressed as;

37+2y

If the first number is 37 more  than 2 times the second  number, then;

x = 37 + 2y

x - 2y = 37 ...2

This shows that the simultaneous equation that fits the expressions are;

x - 2y = 37

x + y = 25

For the expression

A child has a piggy bank full  of $1 and $2 coins totaling  $37.  There are 25 more $1 coins  than there are $2 coins.

Let x be the $1 coins

Let y be the $2 coins

If a child has a piggy bank full  of $1 and $2 coins totaling  $37, then;

x + 2y = 37 ... 1

Also, if there are 25 more $1 coins  than there are $2 coins, then;

x = 25 + y

x - y = 25 ...2

The equivalent expressions for the statement will be;

x + 2y = 37

x - y = 25

This hence leaves us with the last;

An exam that is worth 37  marks contain 25  questions.  The questions are either  worth 1 mark or 2 marks. The resulting simultaneous equation will be;

x + 2y = 37

x + y = 25

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