Answer:
1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)
2) The number of miles they'd have to walk is approximately 13.856 miles
Step-by-step explanation:
1) The distance, direction, and location of the path of the walk the person takes, are listed as follows;
Start location, (0, 0)
6 miles East walk to location, (6, 0)
6 miles Southeast to location, (6 + 3·√2, -3·√2)
3 miles South to location, (6 + 3·√2, -3·√2 - 3)
5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)
2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)
(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)
Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)
The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)
d = (16 + √2)/2)·i - (6+11·√2)/2)·j
2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;
[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]
Therefore;
If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]
