find thd length of the missing sides

Answer:
y = 8 √3
x = 4 √3
Step-by-step explanation:
y sin 60 = 12
y (√3/2) = 12
y = 8√3
y cos 60 = x
(8√3) ÷2 = x
x = 4 √3
Answer:
x = 4[tex]\sqrt{3}[/tex] , y = 8[tex]\sqrt{3}[/tex]
Step-by-step explanation:
The ratio of the sides of a 30- 60- 90 triangle are
x : x[tex]\sqrt{3}[/tex] : 2x
From the diagram
x[tex]\sqrt{3}[/tex] = 12 ( divide both sides by [tex]\sqrt{3}[/tex] )
x = [tex]\frac{12}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ( rationalising the denominator )
= [tex]\frac{12\sqrt{3} }{3}[/tex]
x = 4[tex]\sqrt{3}[/tex]
Then
y = 2x = 2 × 4[tex]\sqrt{3}[/tex] = 8[tex]\sqrt{3}[/tex]