Answer:
[tex]\displaystyle \frac{1}{9}[/tex]
Step-by-step explanation:
Hi there!
This question is asking us what the value of y is when x is -2, hence the point (-2,y).
[tex]y=3^x[/tex]
To find y, replace x in the equation with -2 and evaluate:
[tex]y=3^-^2[/tex]
When [tex]a^-^n[/tex] where n>0, [tex]a^-^n=\displaystyle \frac{1}{a^n}[/tex]:
[tex]y=\displaystyle \frac{1}{3^2} \\\\y=\displaystyle \frac{1}{9}[/tex]
I hope this helps!
