Answer:
1
11
111
1111
11111
Explanation:
Given
The above QBasic code
Required
The output
The iteration on the third line is repeated 5 times; i.e. for values of j from 1 to 5.
In each iteration, the value of N is printed and the next value is calculated.
Initially, the value of N is 1 ---- on line 2
So, 1 is printed first. The next value of N is as follows:
[tex]N = 10 * N + 1[/tex] --- we keep replacing N (on the right-hand side) with current N value.
So, we have:
[tex]N = 10 * 1 + 1 =11[/tex]
[tex]N = 10 * 11 + 1 = 111[/tex]
[tex]N =10 *111+1 = 1111[/tex]
[tex]N =10 *1111+1 = 11111[/tex]
