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Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and a 1k ohm load are connected the DC output voltage is 14V. What is... The value of the capacitor? The value of the peak to peak ripple voltage?

Respuesta :

okpalawalter8

Answer:

[tex]V_{pp}=2V[/tex]

Explanation:

Source Voltage [tex]V= 120V[/tex]

Frequency [tex]f=60Hz[/tex]

Peak output voltage [tex]Vp=15V[/tex]

Peak Output Voltage with filter [tex]V_p'=14V[/tex]

Generally the equation for Peak to peak voltage is mathematically given by

[tex]V_p'=V_p-\frac{V_{pp}}{2}[/tex]

Therefore

[tex]V_{pp}=2(V_p-v_p')[/tex]

[tex]V_{pp}=2(15-14)[/tex]

[tex]V_{pp}=2V[/tex]

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