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Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from the line at points F and E to form an isosceles triangle with point D. Angle DEF measures 75°. What is the measure of angle CFD?

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MrRoyal

Answer:

[tex]\angle CFD =105^o[/tex]

Step-by-step explanation:

Given

[tex]\angle D FE = \angle DE F = 75^o[/tex]

See attachment

Required

Determine the measure of [tex]\angle CFD[/tex]

[tex]\angle CFD[/tex] and [tex]\angle DFE[/tex] are on a straight line.

So:

[tex]\angle CFD + \angle DFE = 180^o[/tex] --- angle on a straight line

Substitute known values

[tex]\angle CFD + 75^o = 180^o[/tex]

Collect like terms

[tex]\angle CFD =- 75^o + 180^o[/tex]

[tex]\angle CFD =105^o[/tex]

Ver imagen MrRoyal

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