A Ball A and a Ball B collide elastically. The initial momentum of Ball A is -2.00kgm/s and the initial momentum of Ball B is -5.00kgm/s. Ball A has a mass of 4.00kg and is traveling at 2.50 m/s after the collision. What is the velocity of ball B if it has a mass of 6.50kg?

Respuesta :

The velocity of B after the collision is obtained as -2.6 m/s.

What is the principle of conservation of momentum?

Now we now that the  principle of conservation of momentum states that the momentum before collision is equal to the momentum after collision.

Thus;

(-2.00kgm/s) + ( -5.00kgm/s) = ( 4.00kg * 2.50 m/s) + ( 6.50kg * v)

-7 = 10 + 6.5v

-7 - 10 = 6.5v

v = -7 - 10 /6.5

v = -2.6 m/s

Hence, the velocity of B after the collision is obtained as -2.6 m/s.

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