Find the equation of the line with the slope 3/2 through the point (-6,2)

Step-by-step explanation:
y-y1=slope (x-x1)
where x1=-6,y1=2 and slope=3÷2
y-2=3÷2{x-(-6)}
y-2=3÷2(x+6)
y-2=(3x+18)÷2 cross multiply
2y-4=3x+18 collect like terms
2y=3x+18+4
2y=3x+22....ans