Answer:
Step-by-step explanation:
In reality it is : [tex](x-\frac{1}{x} )^5\\[/tex]
[tex]Pascal'sTriangle\\\\\begin{array}{cccccc}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\\1&5&10&10&5&1\\\end{array}\\\\\\(x-\frac{1}{x} )^5\\\\=x^5+5*x^4*\frac{1}{x} *(-1)+10*x^3*\frac{1}{x^3}*(-1)+5*x*\frac{1}{x^4} +\frac{1}{x^5} *(-1)\\\\\\\boxed{(x-\frac{1}{x} )^5=x^5-5x^3+10x-\frac{10}{x} +\frac{5}{x^3} -\frac{1}{x^5} }[/tex]
