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Miguel's coffee shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Miguel $5.95 per pound, and Type B coffee costs $4.65 per pound. This month's blend used three times as many pounds of Type B coffee as Type A, for a total cost of $796.00. How many pounds of Type A coffee were used?

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Answer:  40 lb of Type A

Step-by-step explanation:3 pounds of Type B and 1 pound of Type A will give 4 pounds of mix at a cost of ...  3($4.65) +($5.95) = $19.90Then $796 is the cost equivalent of 796/19.90 = 40 times that 4-lb mix. Since each instance of that 4-lb mix has 1 lb of Type A, $796 worth of blend has 40 lb of Type A coffee._____Additional commentIf you'd like to do this using a variable, you can let 'a' represent the amount of Type A coffee used. Then (3a) is the amount of Type B, and the total cost is ...  5.95a +4.65(3a) = 796  19.90a = 796 . . . . . . . . simplify  a = 796/19.90 = 40 . . . as above___There will be 120 lb of Type B coffee in that amount of blend.

ajeigbeibraheem

The amount of Type A coffee that were used is 40 pounds.

What are word problems in Algebra?

Word problems in Algebra can be solved by correctly identifying the parameters given and the one(s) meant to be solved with the appropriate use of arithmetic operations.

From the given information;

  • Type A coffee costs Miguel $5.95 per pound
  • Type B coffee costs $4.65 per pound.

For this month, the equation can be expressed as:

  • A + 3A

Thus;

  • 5.95A + 3(4.65)A = 796.00
  • 5.95A +13.95A = 796.00
  • 19.9A = 796.00
  • A = 796.00/19.9
  • A = 40

Therefore, we can conclude that the amount of pounds of type A coffee that were used is 40 pounds.

Learn more about word problems here:

https://brainly.com/question/21405634

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