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Answer:
g(f(x)) = √((x²+5)/(x²+4))
Step-by-step explanation:
[tex]g(f(x))=g(\dfrac{1}{x^2+4})=\sqrt{\dfrac{1}{x^2+4}+1}=\sqrt{\dfrac{1+x^2+4}{x^2+4}}\\\\\boxed{g(f(x))=\sqrt{\dfrac{x^2+5}{x^2+4}}}[/tex]
I prefer this compact form, but some may want the denominator rationalized. This means the expression becomes ...
[tex]g(f(x))=\sqrt{\dfrac{(x^2+5)(x^2+4)}{(x^2+4)^2}}\\\\\boxed{g(f(x))=\dfrac{\sqrt{x^4+9x^2+20}}{x^2+4}}[/tex]
