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While on a scavenger hunt, a student walks 500 m north, 200 m east, 300 south and finally 400 m west What is the net displacement and direction of the student?​

Respuesta :

ferrybukantoro

Answer:

282.84 m toward Northwest

Explanation:

d = √(500-300)² + (400-200)²

=√(200²+200²)

= √(40000+40000)

= √ 80000

= 282.84 m

direction => Northwest

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~Pythagoras

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[tex]d = \sqrt{(500 - 300)^2 + (400 - 200)^2 } [/tex]

[tex]d = \sqrt{200^{2} + 200 ^{2} } [/tex]

[tex]d = \sqrt{40.000 \times 2} [/tex]

[tex]d = \sqrt{80.000} [/tex]

[tex]d \approx 282,84 m[/tex]

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