Answer:
2.98 g CO2
Explanation:
1. Balance the chemical equation
1 Fe2O3 + 3CO -> 2Fe + 3CO2
2. Use periodic table to find mass from each CO2 and Fe2O3
3. Calculate
3.60 g Fe2O3 x [tex]\frac{1 mol Fe2O3}{159.69 g Fe2O3}x\frac{3 mol CO2}{1 mol Fe2O3}[/tex] x[tex]\frac{44.01 g CO2}{1 mol CO2}[/tex] = 2.98 g CO2
The grams of CO, produced when 3.60 g of Fe 0 reacts with excess CO is 2.98 grams Co2.
Mass is the quantity of matter of a physical body.
The balanced equation is
[tex]\rm Fe_2O_3 + CO - > Fe + CO_2[/tex]
The calculation is
[tex]3.60 g \;Fe_2O_3 \times \dfrac{ 1 mol\;Fe_2O_3}{159.69} \times \dfrac{3 mol CO_2}{1 mol \;Fe_2O_3 } \times \dfrac{44.01\;CO_2}{1 mol\; CO_2} = 2.98 g\;CO_2[/tex]
Thus, the grams of CO, produced when 3.60 g of Fe 0 reacts with excess CO is 2.98 grams Co2.
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