Answer:
[tex]\boxed {\boxed {\sf d= 11}}[/tex]
Step-by-step explanation:
We are asked to find the distance between 2 points. We will use the distance formula.
[tex]d= \sqrt{ (x_2-x_1)^2+(y_2-y_1)^2[/tex]
In this formula, (x₁ , y₁) and (x₂ , y₂) are the points. We are given the points (-6, -7) and (5, -7). If we match the value and the corresponding variable, we see that:
- x₁ = -6
- y₁ = -7
- x₂ = 5
- y₂ = -7
Substitute these values into the formula.
[tex]d= \sqrt{(5- -6)^2 + (-7--7)^2[/tex]
Solve inside the parentheses. Remember that two back-to-back negative signs become a plus sign.
- (5 - - 6) = (5 +6) = 11
- ( -7 - - 7) = (-7 +7) = 0
[tex]d= \sqrt{ (11)^2+(0)^2[/tex]
Solve the exponents.
- (11)² = 11 * 11 = 121
- (0)² = 0*0= 0
[tex]d= \sqrt{(121)+(0)[/tex]
Add.
[tex]d= \sqrt{121}[/tex]
[tex]d=11[/tex]
The distance between (-6, -7) and (5, -7) is 11.
