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A: What is the perimeter of HOUSE?
perimeter of HOUSE =


(round to the nearest hundredth - two decimal places)


B: What is the length of OH?

(round to the nearest thousandth - three decimal places)


C: What is the midpoint of OU?


D: Which is longer, OH or EH?


E: What is the perimeter of the triangle HOU?


perimeter of triangle HOU


(round to the nearest hundredth - two decimal points)

A What is the perimeter of HOUSE perimeter of HOUSE round to the nearest hundredth two decimal places B What is the length of OH round to the nearest thousandth class=

Respuesta :

First calculate distances or lengths(Refer to attachment)

A:-

[tex]\\ \sf\longmapsto Perimeter=Sum\:of\:sides[/tex]

[tex]\\ \sf\longmapsto 5.3+9+11+9+9.7[/tex]

[tex]\\ \sf\longmapsto 15+29[/tex]

[tex]\\ \sf\longmapsto 44[/tex]

B:-

Refer to the attchment

C:-

[tex]\\ \sf\longmapsto \left(\dfrac{1+4}{2},\dfrac{1+6}{2}\right)[/tex]

[tex]\\ \sf\longmapsto \left(\dfrac{5}{2},\dfrac{7}{2}\right)[/tex]

D:-

EH>OH

E:-

[tex]\\ \sf\longmapsto Perimeter[/tex]

[tex]\\ \sf\longmapsto 9.7+5.3+9[/tex]

[tex]\\ \sf\longmapsto 24[/tex]

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mhanifa

Answer:

The coordinates of the HOUSE:

  • H(-7, 1), O(1, 6), U(4, 1), S(4, -8), E(-7, -8)

Part A

To find the perimeter first find the length of each side:

  • OH = [tex]\sqrt{(1 +7)^2+(6-1)^2} = \sqrt{64+25} =\sqrt{89}[/tex] β‰ˆ 9.43 units
  • OU = [tex]\sqrt{(4-1)^2+(1-6)^2} = \sqrt{9+25} = \sqrt{34}[/tex] β‰ˆ 5.83 units
  • US = 1 - (-8) = 9 units
  • SE = 4 - (-7) = 11 units
  • EH = 1 - (-8) = 9 units

The perimeter is:

  • P = 9.43 + 5.83 + 9 + 11 + 9 = 44.26 units

Part B

  • OH = 9.43 units (see part A)

Part C

Use midpoint formula:

  • x = (4 + 1)/2 = 2.5
  • y = (1 + 6)/2 = 3.5

The point is (2.5, 3.5)

Part D

  • OH = 9.43 units > EH = 9 units (see part A)

Part E

  • P(Ξ”HOU) = OH + OU + HU (or SE) = 9.43 + 5.83 + 11 = 26.26 units

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