Respuesta :

First find Divisor

  • Two zeros are -3,-2

[tex]\\ \sf\longmapsto x^2-(-3-2)+(-3)(-2)[/tex]

[tex]\\ \sf\longmapsto x^2+5x+6[/tex]

Dividend given by

[tex]\\ \sf\longmapsto x^4-x^3-16x^2+4x+48[/tex]

We know

[tex]\boxed{\sf Dividend=Divisor\times Quotient +Remainder}[/tex]

  • Remainder is 0

[tex]\\ \sf\longmapsto Dividend=Divisor\times Quotient[/tex]

[tex]\\ \sf\longmapsto Quotient=\dfrac{Dividend}{Divisor}[/tex]

[tex]\\ \sf\longmapsto \dfrac{x^4-x^3-16x^2+4x+48}{x^2+5x+6}[/tex]

[tex]\\ \sf\longmapsto x^2-6x+8[/tex]

Now factor

[tex]\\ \sf\longmapsto x^2-6x+8=0[/tex]

[tex]\\ \sf\longmapsto x^2-4x-2x+8=0[/tex]

[tex]\\ \sf\longmapsto x(x-4)-2(x-4)=0[/tex]

[tex]\\ \sf\longmapsto (x-4)(x-2)=0[/tex]

[tex]\\ \sf\longmapsto x-4=0\:or\:x-2=0[/tex]

[tex]\\ \sf\longmapsto x=4\:or\:x=2[/tex]

Hence all zeros are

  • 2,-2,-3,4