The inequality that would be used to solve for the LEAST amount of money he needed to deposit to avoid a fee is 638.54 - 159.50 + x ≥ $500
The given parameters:
initial amount of money in Malcom's account = $638.54
a constant balance to be maintained to avoid a fee = $500
amount to be withdrawn today = $159.50
To find:
- inequality that would be used to solve for the LEAST amount of money he needed to deposit to avoid a fee
Let the LEAST amount = x
Here are basic things to note in order to form the equation:
- The money going into the account must be added
- The amount to be withdrawn will be subtracted
- Finally, the total amount must be greater or equal to  $500
Considering the above explanation, the inequality becomes;
638.54 + x - 159.50 ≥ $500
Rearrange to match the given options;
638.54 - 159.50 + x ≥ $500
Thus, the inequality that would be used to solve for the LEAST amount of money he needed to deposit to avoid a fee is 638.54 - 159.50 + x ≥ $500
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