Answer:
Halfway between B and A on the return leg.
Explanation:
Your average SPEED for the entire trip will equal your constant speed as the time and distance increase at proportionate rates.
Your average VELOCITY will equal your constant speed while you travel from A to B because time and displacement are increasing at proportionate rates.
When you turn around at B to return, your Displacement is now decreasing while your travel time continues to increase, so your average velocity decreases.
Lets say the distance from A to B is 90 km and your constant speed is 30 km/hr.
your average speed is 30 km/hr because you took 6 hrs to travel 180 km
We want to find your position when your average velocity is 30/3 = 10 km/hr
it took 3 hrs to go 90 km from A to B. Let t be the time lapsed since turn around
your displacement is given by d = 90 - 30(t)
and your total time of travel is t + 3 hrs
v = d/t
10 = (90 - 30t) / (t + 3)
10(t + 3) = (90 - 30t)
10t + 30 = 90 - 30t
40t = 60
t = 1.5 hrs
This will occur when you are halfway between B and A
We have that the Magnitude of Velocity is equal to Speed when you are one-third of the way back to A from B.
[tex]1/3V=S[/tex]
From the Question we are told that
Trip from city A to B and back
Generally
Velocity
This is defined as the distance cover over time ratio with respect to direction
Speed
This is the distance cover over time ratio with no regard to direction.
Having said this
Magnitude of Velocity with respect to direction of back forth has a net of zero
Magnitude Speed of increases as it returns to A after going to B
In conclusion
The Magnitude of Velocity is equal to Speed when You are one-third of the way back to A from B.
[tex]1/3V=S[/tex]
For more information on this visit
brainly.com/question/17127206
