The average velocity of the object over the given interval (from t=1 to t=4) is 1 m/s
Given that; S(t) = 3√t
Also, the interval is from t = 1 to t = 4
meaning t₁ = 1 and t₂ = 4
we know that;
Average Velocity = [ Displacement / time ] = [tex]\frac{ S(t_2) - S(t_1) }{ t_2 - t_1 }[/tex]
since its given that, S(t) = 3√t
So, Average Velocity = [tex]\frac{ (3\sqrt{t_2}) - (3\sqrt{t_1)} }{{t_2} - t_1}[/tex]
we substitute in the value of t₁ and t₂
[tex]Average Velocity = \frac{ (3\sqrt{4}) - (3\sqrt{1)} }{{4} -1}[/tex]
[tex]Average Velocity = \frac{ 3(2) - 3({1)} }{{4} -1}[/tex]
[tex]Average Velocity = \frac{ 6 - 3}{3}[/tex]
[tex]Average Velocity = \frac{ 3}{3}[/tex]
Average Velocity = 1 m/s
Therefore, the average velocity of the object over the interval from t=1 to t=4 is 1 m/s
Also Visit; https://brainly.com/question/862972?referrer=searchResults
