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In a three-person tug-of-war, three ropes are tied at a point. Gary is pulling due East with a force of 650 Newtons, June is pulling due North with a force of 450 Newtons, and Levi is pulling the third rope. The knot in the middle is not moving. What is the magnitude of Levi's effort?
A) 34.7 Newtons
B) 55.3 Newtons
C) 550 Newtons
D) 790.6 Newtons​

Respuesta :

Answer:

Its D) 790.6

Step-by-step explanation:

All I can say is that I aced the test so.

oladayoademosu

The answer to the question what is the magnitude of Levi's effort is D 790.6 N

Since Gary is pulling due East with a force of 650 Newtons, June is pulling due North with a force of 450 Newtons, the force due to Levi will be equal to the resultant force from Gary and June.

Since both Gary and June pull due East and due North respectively and these directions are perpendicular to each other, their resultant force is

R = √[(650 N)² + (450 N)²]

R = √[422500 N² + 202500 N²]

R = √[625000 N²]

R = 790.57 N

R ≅ 790.6 N

Since the resultant force due to Gary and June is 790.6 N, this is equal to the magnitude of Levi's effort since the knot does not move.

So, the magnitude of Levi's effort is 790.6 N

So, the answer to the question what is the magnitude of Levi's effort is D 790.6 N

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